(Solved): You are designing an electron accelerator to bring a stationary electron to a speed of (2.20810 ...

You are designing an electron accelerator to bring a stationary electron to a speed of $$\left(2.208\times 10^{?}6\right)\mathrm{m}/\mathrm{s}$$ in a uniform electric field. If the distance travelled is $$\left(8.45\times 10^{?}?2\right)$$ metres, what must the magnitude of the electric field be in $$\mathrm{N}/\mathrm{C}$$ ? Calculate the net electric field in $$N/C$$ generated at point $$P,r=\left(1.806\times 10^{?}?1\right)$$ metres from charge $$q1=\left(6.60\times 10^{?}0\right)\mathrm{nC}$$. You do not need to enter a unit vector in your answer, but if the answer is negative, you must include the negative sign. Note: Your answer is assumed to be reduced to the highest power possible. Find the net electric field in $$\mathrm{N}/\mathrm{C}$$ at point $$\mathrm{P}$$, where $$q1=\left(?7.02\times 10^{?}0\right)\mathrm{nC},\mathrm{r}1=$$ $$\left(6.6290\times 10^{?}?1\right)$$ metres, $$q2=\left(5.618\times 10^{?}0\right)nC$$ and $$r2=\left(6.2810\times 10^{?}?1\right)$$ metres. You do not need to include a unit vector in your answer, but must include a minus sign if the field direction is in the negative $$x$$ direction.