(Solved): will rate if correct! all part of same question The I vs t graph shown below is for an LR circuit w ...

will rate if correct! all part of same question

The I vs $$t$$ graph shown below is for an LR circuit with a battery. Determine the time constant of the LR circuit. $$\begin{array}{l}?=\\ \text{ If }L=9\mathrm{H}\text{, determine }R.\\ R=\end{array}$$ Second graph The I vs $$\mathrm{t}$$ graph shown below is for an LR circuit without a battery. Determine the time constant of the LR circuit. $$?=$$ If $$L=6\mathrm{H}$$, determine $$R$$. $$R=?$$ For an LR Circuit, $$?=\frac{L}{R}$$ where $$?$$ is the time constant with mks units of s. There are two cases we care about. LR Circuit with a battery: $$I=I_{\max }\left(1?e^{?t/?}\right)$$ $$I_{\max }=\frac{V_O}{R}$$ where $$V_o$$ the voltage of the battery. When $$t=?,I?0.632?I_{\max }$$. LR Circuit without a battery: $$I=I_i{e}^{?t/?}$$ $$I_i$$ is the initial current of the inductor. When $$t=?,I?0.368?l_i$$