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(Solved): Which fucntion of \( u(x, y) \) of the Laplace equation \( \frac{\partial^{2} u}{\partial x^{2}}+\f ...
Which fucntion of \( u(x, y) \) of the Laplace equation \( \frac{\partial^{2} u}{\partial x^{2}}+\frac{\partial^{2} u}{\partial y^{2}}=0,0
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Let us start by writing u(x,y)=X(x).Y(y) Substituting this in the Laplace Equation we get, d2udx2+d2udy2=0 Yd2Xdx2+Xd2Ydy2=0 Dividing by XY we get: 1X
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