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(Solved): What mass (in g) of \( \mathrm{AgCl} \) is formed from the reaction of \( 75.0 \mathrm{~mL} \) of a ...
What mass (in g) of \( \mathrm{AgCl} \) is formed from the reaction of \( 75.0 \mathrm{~mL} \) of a \( 0.078 \mathrm{M} \) \( \mathrm{AgC}_{2} \mathrm{H}_{3} \mathrm{O}_{2} \) solution with \( 55.0 \mathrm{~mL} \) of a \( 0.109 \mathrm{M} \mathrm{MgCl}_{2} \) solution? \[ 2 \mathrm{AgC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{MgCl}_{2}(a q) \rightarrow 2 \mathrm{AgCl}(s)+\mathrm{Mg}_{2}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}(a q) \] \( 1.70 \mathrm{~g} \) \[ 0.859 \mathrm{~g} \] \[ 2.56 \mathrm{~g} \] \[ 0.838 \mathrm{~g} \] \[ 1.72 \mathrm{~g} \]
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Soln- mass (in g) of AgCl is formed from the reaction---? Given - 75.0 mL of a 0.078 M AgC2H3O2 solution Moles = M*V 1mL = 0.001L/mL V = 75.0mL*0.001L/mL = 0.075 L Moles = 0.078M*0.075L =
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