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(Solved): What is the structure? (c3h5cl3) MASS 1 H NMR 300MHz Wavenumber (cm1) 13C/DEPT NMR 75.5MHz Wl 175 ...

What is the structure? (c3h5cl3)

$MASS \( { }^{1} \) H NMR \( 300 \mathrm{MHz} \) Wavenumber \( (\mathrm{cm}-1) \) \( { }^{13} \mathrm{C} / \mathrm{DEPT} \) NM$

MASS

^{1}

H NMR

300 MHz

Wavenumber

(cm ? 1)

^{13} C / DEPT

NMR

75.5 MHz

Wl

175170

1

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MF = C3H5Cl3 degree of unsaturation = 3 + 1

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