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(Solved): Water has a vapor pressure of \( 18.0 \) torr and a density of \( 0.997 \mathrm{~g} / \mathrm{mL} \ ...
Water has a vapor pressure of \( 18.0 \) torr and a density of \( 0.997 \mathrm{~g} / \mathrm{mL} \). Methanol \( \left(\mathrm{CH}_{3} \mathrm{OH}\right) \) has a vapor pressure of \( 126.8 \) torr and a density of \( 0.791 \mathrm{~g} / \mathrm{mL} \). Assuming a mixture of the two behaved ideally and followed Raoult's Law, what would you predict to be the vapor pressure (in torr) of a solution containing \( 525 \mathrm{~mL} \) of water and \( 345 \mathrm{~mL} \) of methanol?
The parameters are given ; Volume solvent, water = 525 mL ; density of water = 0.997 g/mL ; Mass of solvent = volume of solvent x density of water = 525 mL x 0.997 g/mL = 523.4 g ; moles solvent = mass of solvent / molar mass of solvent = 523.4 g/ 18