(Solved): visible light is an electromagnetic wave, in which the electric and magnetic fields propagate as t ...

visible light is an electromagnetic wave, in which the electric and magnetic fields propagate as transverse waves. For a harmonic wave polarized in the \( x \) direction and propagating in the \( z \) direction in empty space, the fields have the form \[ E_{x}(z, t)=E_{0} \cos (k z-\omega t), \] \[ B_{Y}(z, t)=B_{0} \cos (k z-\omega t) \text {. } \] The wavelength \( \boldsymbol{\lambda} \) is given below. DATA: \( \quad \lambda=650 \mathrm{~nm} ; \quad E_{0}=150 \mathrm{~V} / \mathrm{m} \). Determine the parameter \( \mathrm{k} \). (in \( m^{\wedge}-1 \) ) A: \( 1.508 \times 10^{6} \) C: \( 3.171 \times 10^{6} \) Tries \( 0 / 12 \) Determine the average field energy density \( \mathrm{u} \) in the wave. (in \( ]^{*} m^{\wedge}-3 \) )