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(Solved): Using a BS107 N-Channel MOSFET, design a common-source, single-stage amplifier (Fig. 2) that has a ...




Using a BS107 N-Channel MOSFET, design a common-source, single-stage amplifier (Fig. 2) that has a voltage gain of \( -6 \).
Using a BS107 N-Channel MOSFET, design a common-source, single-stage amplifier (Fig. 2) that has a voltage gain of \( -6 \). Assume it has a \( 10 \mathrm{kD} \) capacitively-coupled load resistor with a \( 15 \mathrm{~V} \) power supply \( \left(\mathrm{V}_{D D}\right) \) and quiescent drain current of \( 6 \mathrm{~mA} \) Figure 1: MOSFET CS Amplifier Design*: Follow the steps below to design the amplifier shown in Figure 1. Note that, as with the BJT amplifier from an earlier lab, we will be using a four-resistor scheme to bias the MOSFET in its quiescent range for optimum performance. Assume \( \mathrm{V}_{\mathrm{T}} \) is \( 4 \mathrm{~V} \). Given specifications: 1. From the input \( \left(\mathrm{c}_{-}-2 \sqrt{K_{,} l_{\infty 0}}\right) \) 2 From the gain equation, \( 1,--\frac{R_{0}}{}\left(\frac{R_{0} R_{2}}{R_{p}+R_{C}}\right) \), find \( R_{b} \). 3. Write KVL equation for output loop in terms of \( \mathrm{V}_{D 0}, \mathrm{I}_{07}, \mathrm{R}_{\mathrm{s}} \), \( \mathrm{R}_{\mathrm{p}} \), and \( \mathrm{V}_{\mathrm{DS}} \), Solve for \( \mathrm{R}_{\mathrm{s}} \). 4. From the output characteristic curve, find \( V_{G S} \). Hint : \( \left[I_{D}=K_{s}\left(V_{G S}^{2}-2 V_{T} V_{G s}+V_{T}^{2}\right)\right] \) (You will get two values for \( \mathrm{V}_{G S} \); use the smaller value.) s. Write a KVL equation around the input loop of the equivalent circuit. \( \left(V_{\sigma}=V_{\mathrm{G}}+l_{s} R_{S}\right) \) Solve for \( \mathrm{V}_{\mathrm{G}} \). 6. Choose \( \left(\mathrm{R}_{1}+\mathrm{R}_{2}\right)=150 \mathrm{k} \) ]. Write a voltage divider equation for \( V_{G} \) and plug in \( 150 \mathrm{k} \square \) for \( \left(R_{1}+R_{2}\right) \). Now the only unknown in the equation is \( R_{2} \). Solve for \( R_{2} \). With the \( R_{2} \) known, solve for \( R_{1} \).


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Solution:: Before doing 3,4,5,6 First we have to Calculate RD and gm gm =2 ?(knIoQ) = 2?(0.00176 × 6.2m) = 6.6066 mA/v AV = gm [RD × RL/RD + RL] = +6
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