(Solved): Use the force method to determine the force in member BC. Take a=5kN,b=14kN,AB=CD=3m,AD=BC=4m ...

Use the force method to determine the force in member $$BC$$. Take $$\mathbf{a}=5\mathrm{kN},\mathbf{b}=14\mathrm{kN},AB=CD=3\mathrm{m},AD=BC=4\mathrm{m}$$ and $$EA$$ the same for all the members. The members are numbered as follows: Please solve the problem by releasing member 2 and following the steps below: Part 1) Calculate the internal forces in the primary structure. a) $$N_1=\mathrm{kN}$$ b) $$N_2=\mathrm{kN}$$ c) $$N_3=\mathrm{kN}$$ d) $$N_4=$$ e) $$N_5=\mathrm{kN}$$ f) $$N_6=\mathrm{kN}$$ Part 2) Calculate the internal forces in the redundant structure. a) $$n_1=\mathrm{kN}$$ b) $$n_2=\mathrm{kN}$$ c) $$n_3=\mathrm{kN}$$ d) $$n_4=?\mathrm{kN}$$ e) $$n_5=\mathrm{kN}$$ f) $$n_6=\mathrm{kN}$$ Part 3) Calculate the force in member $$BC$$. $$F_{BC}=\mathrm{kN}$$