Use combustion analysis to determine empirical and molecular formulas (hydrocarbons).\\nWhen
5.428
grams of a hydrocarbon,
C_(x)H_(y)
, were burned in a combustion analysis apparatus, 16.44 grams of
CO_(2)
and 8.415 grams of
H_(2)O
were produced.\\nIn a separate experiment, the molar mass of the compound was found to be
58.12(g)/(m)ol
. Determine the empirical formula and the molecular formula of the hydrocarbon.\\nEnter the elements in the order presented in the question.\\nempirical formula
=
\\nmolecular formula
=
\\nShow Approach