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(Solved): Use a \( 0.05 \) level of significance to test whether the temperature level has an effect on the ...



Use a \( 0.05 \) level of significance to test whether the temperature level has an effect on the mean yield of the process.
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the \( \rho \)-value. (Round your answe

Use a \( 0.05 \) level of significance to test whether the temperature level has an effect on the mean yield of the process. State the null and alternative hypotheses. \( H_{0} \) : Not all the population means are equal. \[ \begin{array}{l} H_{a}: \mu_{50^{\circ} \mathrm{C}}=\mu_{60^{\circ} \mathrm{C}}=\mu_{70^{\circ}} \mathrm{C} \\ H_{0}: \mu_{50^{\circ} \mathrm{C}}=\mu_{60^{\circ} \mathrm{C}}=\mu_{70^{\circ} \mathrm{C}} \\ H_{a}: \mu_{50^{\circ} \mathrm{C}} \neq \mu_{60^{\circ} \mathrm{C}} \neq \mu_{70^{\circ} \mathrm{C}} \\ H_{0}: \mu_{50^{\circ} \mathrm{C}} \neq \mu_{60^{\circ} \mathrm{C}} \neq \mu_{70^{\circ} \mathrm{C}} \\ H_{\mathrm{a}}: \mu_{50^{\circ} \mathrm{C}}=\mu_{60^{\circ} \mathrm{C}}=\mu_{70^{\circ}} \mathrm{C} \\ H_{0}: \mu_{50^{\circ} \mathrm{C}}=\mu_{60^{\circ} \mathrm{C}}=\mu_{70^{\circ} \mathrm{C}} \\ H_{a}: \text { Not all the population means are equal. } \\ H_{0}: \text { At least two of the population means are equal. } \\ H_{a}: \text { At least two of the population means are different. } \end{array} \] Find the value of the test statistic. (Round your answer to two decimal places.) Find the \( \rho \)-value. (Round your answer to four decimal places.) \( p \)-value \( = \) State your conclusion. Do not reject \( H_{0} \). There is not sufficient evidence to conclude that the mean yields for the three temperatures are not equal. Do not reject \( H_{0} \). There is sufficient evidence to conclude that the mean yields for the three temperatures are not equal. Reject \( H_{0} \). There is not sufficient evidence to conclude that the mean yields for the three temperatures are not equal. Reject \( H_{0} \). There is sufficient evidence to conclude that the mean yields for the three temperatures are not equal.


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one-way ANOVA in Excel 50C 60C 60C Anova: Single Factor 35 29 23 23 31 28 SUMMARY 37 33 29 Groups Count Sum Average Variance 38 22 30 50C 5 160 32 44
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