(Solved): Tukey-kramer post hoc test.please explain this part me.  The Tukey-Kramer results do not imply ...

The Tukey-Kramer results do not imply that the "partial shade" and "no shade" treatments have the same mean carbon transfer rates. Assuming that they do would be making the mistake of accepting a null hypothesis. The results merely indicate that a test of their differences did not reject \( \mathrm{H}_{0} \). With the Tukey-Kramer method, the probability of making at least one Type I error throughout the course of testing all pairs of means is no greater than the significance level \( \alpha \).