(Solved): Three forces act on the free-body diagram of a joint on a structure. If the structure is in equilibr ...

Three forces act on the free-body diagram of a joint on a structure. If the structure is in equilibrium and FA = 4.20 kN, what are FB and FC?

Copyright @ 2008 Pearson Prentice Hall, Inc. Three forces act on the free-body diagram of a joint on a structure. If the structure is in equilibrium and \( \mathrm{F}_{\mathrm{A}}=4.20 \mathrm{kN} \), what are \( \mathrm{F}_{\mathrm{B}} \) and \( \mathrm{F}_{\mathrm{C}} \) ? \[ \begin{array}{l} F_{B}=2.70 \mathrm{kN} \& F_{C}=1.87 \mathrm{kN} \\ F_{B}=1.87 \mathrm{kN} \& F_{C}=2.70 \mathrm{kN} \\ F_{B}=1.84 \mathrm{kN} \& F_{C}=3.33 \mathrm{kN} \\ F_{B}=3.33 \mathrm{kN} \& F_{C}=1.84 \mathrm{kN} \end{array} \]