(Solved): There are two different compounds of phosphorous and fluorine. - In \( \mathrm{PF}_{6} \), the mass ...

There are two different compounds of phosphorous and fluorine. - In \( \mathrm{PF}_{6} \), the mass of fluorine per gram of phosphorous is \( 4.86 \mathrm{~g} \mathrm{~F} / \mathrm{g} P \) - In the other compound, PF , the mass of fluorine per gram of phosphorous is \( 2.43 \mathrm{~g} \mathrm{~F} / \mathrm{g} \mathrm{P} \). What is the value of \( X \) for the second compound? Express your answer as an integer. View Available Hint(s) \( X= \)