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(Solved): The volume of the solid region in the first octant bounded by the cones z=\sqrt((x^(2)+y^(2))/(3)), ...



The volume of the solid region in the first octant bounded by the cones

z=\sqrt((x^(2)+y^(2))/(3))

, and

z=\sqrt(x^(2)+y^(2))

and the sphere

x^(2)+y^(2)+z^(2)=1

A-Use Cylindrical integral B-Use Spherical integral

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