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(Solved): The vapor pressure of liquid pentane, \( \mathrm{C}_{5} \mathrm{H}_{12} \), is \( 100 \mathrm{~mm} ...




The vapor pressure of liquid pentane, \( \mathrm{C}_{5} \mathrm{H}_{12} \), is \( 100 \mathrm{~mm} \mathrm{Hg} \) at \( 260 \
The vapor pressure of liquid pentane, \( \mathrm{C}_{5} \mathrm{H}_{12} \), is \( 100 \mathrm{~mm} \mathrm{Hg} \) at \( 260 \mathrm{~K} \). A sample of \( \mathrm{C}_{5} \mathrm{H}_{12} \) is placed in a closed, evacuated \( 516 \mathrm{~mL} \) container at a temperature of \( 260 \mathrm{~K} \). It is found that all of the \( \mathrm{C}_{5} \mathrm{H}_{12} \) is in the vapor phase and that the pressure is \( 56.0 \mathrm{~mm} \mathrm{Hg} \). If the volume of the container is reduced to \( 336 \mathrm{~mL} \) at constant temperature, which of the following statements are correct? Choose all that apply. The pressure in the container will be \( 100 \mathrm{~mm} \mathrm{Hg} \). Liquid pentane will be present. No condensation will occur. Only pentane vapor will be present. Some of the vapor initially present will condense. 5 question ateimpts remaining


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As we know, PV = nRT Here, nRT is constant. So, P1V1 = P2V2 Given => P1 = 56.00 mm Hg
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