(Solved): The truncated conical container shown to the right is full of a beverage that weighs \( 0.55 \math ...

The truncated conical container shown to the right is full of a beverage that weighs \( 0.55 \mathrm{oz} / \mathrm{in}^{3} \). The container is 9 in. deep, \( 2.8 \) in. across at the base, and \( 3.6 \) in. across at the top. A straw sticks up 4 in. above the top. How much work does it take to suck up the beverage through the straw (neglecting friction)? Let \( y=0 \) correspond to the bottom of the container. Set up the integral that gives the work required, in in.-oz, to suck up the beverage through the straw (neglecting friction). \[ W=\int d y \]