The triglyceride shown can be broken down
to yield a large quantity of ATP. We are going to work our way
through this breakdown process. (Note: We are going to ignore the
glycerol component of this triglyceride.) First, lipases free the
fatty acids from the triglyceride structure, forming three fatty
acyl-CoA molecules. The formation of each free fatty acyl-CoA
requires the equivalent of two ATP, so to free the fatty acids of
this triglyceride, a total of____ATP are invested. These free fatty
acids are now oxidized using a process called beta-oxidation. Each
fatty acid will be converted into a number of acetyl-CoA molecules.
An acetyl group contains two carbons, so fatty acid "A" can be
converted into______acetyl-CoA, requiring_______rounds of
beta-oxidation. Fatty acid "B" can be converted
into______acetyl-CoA, requiring_____rounds of beta-oxidation. Fatty
acid "C" can be converted into_____acetyl-CoA, requiring_____rounds
of beta-oxidation. This would yield a total of____acetyl-CoA from
these fatty acids. You learned that the acetyl-CoA molecules can be
fed into the citrate cycle, so this number of acetyl-CoA molecules
would lead to the formation of______NADH____FADH2, and
____GTP. During each round of beta-oxidation, we harvest one
NADH and one FADH2. This means that if we add up the beta-oxidation
rounds above, we can generate____NADH and ___FADH2. Now, let's
total up the energy harvest from this triglyceride. The ATP yield
from the NADH molecules counted above would be_____. The ATP
yield from the FADH2 molecules counted above would be______.The ATP
yield from the GTP molecules counted above would be_____,Adding
these ATP molecules and subtracting the ATP invested at the start,
we can see that the oxidation of the three fatty acids from this
triglyceride would yield____ATP.