The triglyceride shown can be broken down to yield a large quantity of ATP. We are going to work our way through this breakdown process. (Note: We are going to ignore the glycerol component of this triglyceride.) First, lipases free the fatty acids from the triglyceride structure, forming three fatty acyl-CoA molecules. The formation of each free fatty acyl-CoA requires the equivalent of two ATP, so to free the fatty acids of this triglyceride, a total of____ATP are invested. These free fatty acids are now oxidized using a process called beta-oxidation. Each fatty acid will be converted into a number of acetyl-CoA molecules. An acetyl group contains two carbons, so fatty acid "A" can be converted into______acetyl-CoA, requiring_______rounds of beta-oxidation. Fatty acid "B" can be converted into______acetyl-CoA, requiring_____rounds of beta-oxidation. Fatty acid "C" can be converted into_____acetyl-CoA, requiring_____rounds of beta-oxidation. This would yield a total of____acetyl-CoA from these fatty acids. You learned that the acetyl-CoA molecules can be fed into the citrate cycle, so this number of acetyl-CoA molecules would lead to the formation of______NADH____FADH2, and ____GTP. During each round of beta-oxidation, we harvest one NADH and one FADH2. This means that if we add up the beta-oxidation rounds above, we can generate____NADH and ___FADH2. Now, let's total up the energy harvest from this triglyceride. The ATP yield from the NADH molecules counted above would be_____. The ATP yield from the FADH2 molecules counted above would be______.The ATP yield from the GTP molecules counted above would be_____,Adding these ATP molecules and subtracting the ATP invested at the start, we can see that the oxidation of the three fatty acids from this triglyceride would yield____ATP.