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(Solved): The three displacement vectors in the drawing have magnitudes of \( A=5.05 \mathrm{~m}, B=5.65 \mat ...




The three displacement vectors in the drawing have magnitudes of \( A=5.05 \mathrm{~m}, B=5.65 \mathrm{~m} \), and \( C=3.95
The three displacement vectors in the drawing have magnitudes of \( A=5.05 \mathrm{~m}, B=5.65 \mathrm{~m} \), and \( C=3.95 \mathrm{~m} \). Find the resultant ((a) magnitude and (b) directional angle) of the three vectors by means of the component method. Express the directional angle as an angle above the positive or negative \( x \) axis which is less than \( 90^{\circ} \).


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GIVEN THAT A=5.05 m B=5.65m C=3.95m ?=20deg ?=60deg now the vectors A,B and C are given by -------> A A=Ax +Ay =-A cos(?) i + A sin(?)j where negative
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