(Solved): The solubility products for a series of iodates are
TlIO3 Ksp = ...
The solubility products for a series of iodates are
TlIO3 Ksp = 3.1 x10-6
Cu(IO3)2 Ksp = 1.4 x10-7
Ba(IO3)2 Ksp = 1.57 x10-9
Ce(IO3)3 Ksp = 3.2 x10-10
List these four compounds in order of decreasing molar solubilitity in
a. water.
b. 0.10 M NaIO3.