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(Solved): The reverse reaction of the Haber process is shown below: \[ 2 \mathrm{NH}_{3}(\mathrm{~g}) \right ...



The reverse reaction of the Haber process is shown below:
\[
2 \mathrm{NH}_{3}(\mathrm{~g}) \rightleftharpoons \mathrm{N}_{2}

The reverse reaction of the Haber process is shown below: \[ 2 \mathrm{NH}_{3}(\mathrm{~g}) \rightleftharpoons \mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \] If the concentrations of each of the substances at equilibrium are found to be \( \left[\mathrm{NH}_{3}\right]=0.240 \mathrm{M},\left[\mathrm{H}_{2}\right]= \) \( 0.370 \mathrm{M} \), and \( \left[\mathrm{N}_{2}\right]=0.740 \mathrm{M} \), determine the equilibrium constant, \( \mathrm{K}_{\mathrm{c}} \), for the reaction.


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