(Solved): The Michaelis-Menten rate equation for an enzyme subject to competitive inhibition is Vmax [S] akm ...

The Michaelis-Menten rate equation for an enzyme subject to competitive inhibition is Vmax [S] akm+[S] Beginning with the same Michaelis-Menten starting point, Vo = K?[ES] (1) a new definition of total enzyme as [E?] = [E] + [ES] + [EI] (2) and the definitions of a and K? provided, derive the rate equation for competitive inhibition. Vo = Use the derivation of the Michaelis-Menten equation as a guide, developing a term for [ES]. In the previous steps, you derived the equations [E][I] K? [E] = [E] + [ES] + [E?] = [ES] + [E](1+ [E?] = [ES] + [E]a [ES] Km [S] [E] = [E] = [ES] (1 [1] 1 (1 + 1/1) [ES] = = Vo = + [E?] [S] akm+[S] akm [S] Vmax (3) (5) Derive an equation for V by substituting equation 8 into equation 1. Then, define k? [E?] as Vmax. Show this final equation by selecting the appropriate terms. + (6) (7) [S] - [S]