(Solved): The \( \mathrm{Hg}^{2+} \) ion forms complex ions with \( \mathrm{I} \) as follows: A solution is p ...

The \( \mathrm{Hg}^{2+} \) ion forms complex ions with \( \mathrm{I} \) as follows: A solution is prepared by dissolving \( 0.083 \mathrm{~mol} \mathrm{Hg}\left(\mathrm{NO}_{3}\right)_{2} \) and \( 5.00 \mathrm{~mol} \mathrm{Nal} \) in enough water to make \( 1.0 \mathrm{~L} \) of solution. Calculate the equilibrium concentration of \( \left[\mathrm{Hgl}_{4}{ }^{2}\right] \). \[ \left[\mathrm{Hgl}_{4}{ }^{2-}\right]= \] Calculate the equilibrium concentration of [I]. \[ \text { [1] }]= \] 1 Calculate the equilibrium concentration of \( \left[\mathrm{Hg}^{2}\right] \). \[ \left[\mathrm{Hg}^{2+}\right]= \]