(Solved): The height (in meters) of a projectile shot vertically upward from a peint \( 2 \mathrm{~m} \) abov ...

The height (in meters) of a projectile shot vertically upward from a peint \( 2 \mathrm{~m} \) above ground leval with an initial velecity of \( 22.5 \mathrm{~m} / \mathrm{s} \) is \( \mathrm{h}-2 \mathrm{~h}+22.5 \mathrm{t}-4.9 t^{2} \) after \( t \) secenda. (a) Find the velocity \( (i t i t i t) \) after \( t \) seconds. \[ \forall(t)= \] Find the velecity \( (i n \mathrm{~m} / \mathrm{s}) \) atter 2 seconds and after 4 seconds. \[ \begin{array}{l} v(2)=0 \\ v(4)=m / 2 \\ m / t \\ m \end{array} \] (b) What is the value \( ( \) in \( m / n) \) of \( v(e) \) when the prejectie reaches its maximam hight? \[ r(t)= \] When (in s) dees the projectile reach ite maximum height? (Round your answer te the dacimal plater.) (c) What is the makimum knight (in m)? (Round ypur antwier to hee decimal places.) (d) When \( (i n \). \( ) \) does it het the grounit? (Reound your ativar to two decimal places.) (e) With what velscity \( ( \) in mist does it hit the ground (found your ansier to toro decimal placks.)