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(Solved): the format would look like this Specify all numerical values and addresses as hex(with an x )adecim ...



the format would look like tSpecify all numerical values and addresses as hex(with an \( \mathrm{x} \) )adecimal numbers (with a leading \( \mathrm{x} \)hisFirst the values in the registers:
And here the relevant values in a few memory cells:
Treat \( M[a] \) as the memory array o

Specify all numerical values and addresses as hex(with an )adecimal numbers (with a leading ). 1. The instruction: Memory Address: New value: 2. The instruction: Memory Address: New value: 3. The instruction: Memory Address: New value: First the values in the registers: And here the relevant values in a few memory cells: Treat as the memory array of 16 -bit integers with the index in the range: . In this particular machine state memory cell M[x3002], for example, holds the value . Each of the following instructions modifies a memory cell. For each, what is the address of the modified cell and what value is placed in that cell. Specify all numerical values and addresses as hex(with an )adecimal numbers (with a leading ). 1. The instruction: Memory Address: New value: 2. The instruction: Memory Address: New value: 3. The instruction: Memory Address: New value:


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The instruction: 0011100000000000

Memory Address: x3002
New value : xF004


The instruction 0011100000000000 is an LD instruction, which loads the value at a specified memory address into a register.
The memory address to be loaded is specified in bits 0-11 of the instruction, which in this case is 000000000000. This is an offset of 0, so the address to be loaded is the value of the Base Register (R5) which is ×3002.
Therefore, the address of the modified cell is ×3000 (since the PC will be updated to this value after the instruction execution), and the value placed in that cell will be the contents of memory address ×3002, which is XF004.


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