(Solved): The following radioactive decay of americium provides a constant current of \( \alpha \)-particles ...

The following radioactive decay of americium provides a constant current of \( \alpha \)-particles used in a smoke detector system. \[ { }_{95}^{241} \mathrm{Am} \rightarrow{ }_{2}^{4} \mathrm{He}+{ }_{93}^{237} \mathrm{~Np} \] Calculate the energy of the \( \alpha \)-particles during the decay of americium in \( \mathrm{MeV} \). (Given: Mass of americium-241, \( \mathrm{m}\left({ }_{95}^{241} \mathrm{Am}\right)=241.056829 \mathrm{amu} \); mass of neptunium\( 237, \mathrm{~m}\left({ }_{93}^{237} N p\right)=237.048173 \mathrm{amu} ; \) and mass of helium \( \left.4, \mathrm{~m}\left({ }_{2}^{4} \mathrm{He}\right)=4.002603 \mathrm{amu}\right) \)