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(Solved): The first four terms of the Taylor polynomial for \[ e^{x}=1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !} ...
The first four terms of the Taylor polynomial for \[ e^{x}=1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !} \] use it to approximate the value of \[ e^{0.5} \] , round your answer to three decimal places.