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(Solved): The figure shows block 1 of mass \( 0.240 \mathrm{~kg} \) sliding to the right over a frictionless ...



The figure shows block 1 of mass \( 0.240 \mathrm{~kg} \) sliding to the right over a frictionless elevated surface at a spee

The figure shows block 1 of mass \( 0.240 \mathrm{~kg} \) sliding to the right over a frictionless elevated surface at a speed of \( 7.90 \mathrm{~m} / \mathrm{s} \). The block undergoes an elastic collision with stationary block 2, which is attached to a spring of spring constant \( 1196 \mathrm{~N} / \mathrm{m} \). (Assume that the spring does not affect the collision.) After the collision, block 2 oscillates in SHM with a period of \( 0.130 \) s, and block 1 slides off the opposite end of the elevated surface, landing a distance \( d \) from the base of that surface after falling height \( h=6.50 \mathrm{~m} \). What is the value of \( d \) ? Number Unit


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Given, Mass of block 1 (m1) = 0.240kg Initial velocity of block 1 (u1) = 7.90m/s Spring constant (k) = 1196N/m Time period of oscillation (T) = 0.130s
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