(Solved): The enthalpy of vaporization of Substance \( X \) is \( 27.0 \frac{\mathrm{kJ}}{\mathrm{mol}} \) an ...

The enthalpy of vaporization of Substance \( X \) is \( 27.0 \frac{\mathrm{kJ}}{\mathrm{mol}} \) and its normal boiling point is \( -50 .^{\circ} \mathrm{C} \). Calculate the vapor pressure of \( X \) at \( -95 \). \( { }^{\circ} \mathrm{C} \). Round your answer to 2 significant digits.