(Solved): The design of air-bag depends on stoichiometric precision. The following reaction takes place when ...

The design of air-bag depends on stoichiometric precision. The following reaction takes place when the air-bag is inflated. $$\begin{array}{l}2{\mathrm{NaN}}_3(\mathrm{s})?2\mathrm{Na}(\mathrm{s})+3{\mathrm{N}}_2(\mathrm{g})\\ 6\mathrm{Na}(s)+{\mathrm{Fe}}_2{\mathrm{O}}_3(s)?3{\mathrm{Na}}_2\mathrm{O}(s)+2Fe\end{array}$$ Assume that $$43.4\mathrm{L}$$ of nitrogen gas are needed to inflate an air bag to the proper size. (A) How many grams of $${\mathrm{NaN}}_3$$ must be included in the air-bag to generate this amount of nitrogen (The density of nitrogen gas at this temperature is $$0.916\mathrm{g}/\mathrm{L}$$ ). (B) How much $${\mathrm{Fe}}_2{\mathrm{O}}_3$$ (in grams) must be added to the air-bag for this amount of $${\mathrm{NaN}}_3$$ ? Use the following molar masses: $$\begin{array}{l}{\mathrm{N}}_2=28.02\mathrm{g}/\mathrm{mol}\\ {\mathrm{NaN}}_3=65.01\mathrm{g}/\mathrm{mol}\\ {\mathrm{Fe}}_2{\mathrm{O}}_3=159.69\mathrm{g}/\mathrm{mol}\end{array}$$ Type only the numerical answers in the answer box grams of $${\mathrm{NaN}}_3=$$ $$\mathrm{g}$$ grams of $${\mathrm{Fe}}_2{\mathrm{O}}_3=$$ g