(Solved): The decomposition of hydrogen iodide on finely divided gold at 150C is zero order with respect t ...

The decomposition of hydrogen iodide on finely divided gold at $$150^{?}\mathrm{C}$$ is zero order with respect to HI. The rate defined below is constant at $$1.20\times 10^{?4}\mathrm{mol}/\mathrm{L}?\mathrm{s}$$. $$\begin{array}{l}2\mathrm{HI}(g)\stackrel{\mathrm{Av}}{?}{\mathrm{H}}_2(g)+{\mathrm{I}}_2(g)\\ \text{ Rate }=?\frac{?[\mathrm{HI}]}{?t}=k=1.20\times 10^{?4}\mathrm{mol}/\mathrm{L}?g\end{array}$$ a. If the initial HI concentration was $$0.450\mathrm{mol}/\mathrm{L}$$, calculate the concentration of $$\mathrm{HI}$$ at 21 minutes after the start of the reaction. Concentration $$=$$ b. How long will it take for all of the $$0.450\mathrm{M}\mathrm{HI}$$ to decompose? $$\text{ Time = }\min$$ 9 more group attempts remaining.