(Solved): The common tangent CD of a reversed curve is \( 280.5 \mathrm{~m} \) and has an azimuth from the so ...

The common tangent CD of a reversed curve is \( 280.5 \mathrm{~m} \) and has an azimuth from the south (s) of \( 312^{\circ} 29^{\prime}, B C \) is a tangent of the first curve whose azimuth (s) is \( 252^{\circ} 45^{\prime} \). DE is a tangent of the second curve whose azimuth is \( 218^{\circ} 13^{\prime} \). The radius of the first curve is \( 180 \mathrm{~m} \). The \( \mathrm{VI} \) is at station \( 16+523.37 \). \( B \) is at \( P C \) and \( E \) is at PT. Compute the stationing of the point of tangencies.