(Solved): The circuit shown can be considered an inverting square-root amplifier. Determine \( \mathrm{V}_{\ ...

The circuit shown can be considered an inverting square-root amplifier. Determine \( \mathrm{V}_{\text {out }} \) in terms of \( \mathrm{V}_{\text {in }} \) and compute \( \mathrm{V}_{\text {out }} \) for \( \mathrm{V}_{\text {in }}=4.5 \mathrm{~V} \). Assume \( k^{\prime} \mathrm{W} / \mathrm{L}=2.3 \mathrm{~mA} / \mathrm{V}^{2}, \mathrm{~V}_{T}=0.62 \mathrm{~V}, R_{1}=5 \mathrm{k} \Omega \), and and Ideal OpAmp.