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The Arrhenius equation shows the relationship Part A between the rate constant k and the temperatu ...
The Arrhenius equation shows the relationship Part A between the rate constant k and the temperature T in kelvins and is typically written as The activation energy of a certain reaction is 35.0kJ/mol. At 26?C, the rate constant is k=Ae?Ea?/RT0.0150s?1. At what temperature in degrees Celsius would this reaction go twice as fast? where R is the gas constant (8.314J/mol?K), A is a constant called the frequency factor, and Ea? Express your answer with the appropriate units. is the activation energy for the reaction. However, a more practical form of this equation is lnk1?k2??=REa??(T1?1??T2?1?) which is mathmatically equivalent to lnk2?k1??=REa??(T2?1??T1?1?) where k1? and k2? are the rate constants for a single reaction at two different absolute temperatures (T1?
The Arrhenius equation shows the relationship between the rate constant k and the temperature T Given that the initial rate constant is 0.0150s?1 at an initial temperature of 26?C, what would in kelvins and is typically written as the rate constant be at a temperature of 190.?C for the same reaction described in Part A ? k=Ae?Ea?/RT Express your answer with the appropriate units. where R is the gas constant (8.314J/mol?K), A is a constant called the frequency factor, and Ea? is the activation energy for the reaction. However, a more practical form of this equation is lnk1?k2??=REa??(T1?1??T2?1?) which is mathmatically equivalent to lnk2?k1??=REa??(T2?1??T1?1?) where k1? and k2? are the rate constants for a single reaction at two different absolute temperatures (T?1?