(Solved): The amplifier uses voltage divider bias. Assume the BJT has =150. Assume all capacitors are suffi ...

The amplifier uses voltage divider bias. Assume the BJT has $?=150$. Assume all capacitors are sufficiently large to act as AC shorts. a. Recall the necessary condition for voltage divider bias where one can ignore the base current: Voltage Divider Bias Condition: $R_{B2}?\frac{?R_E}{10}$ Note: ${\mathrm{R}}_{\mathrm{B}2}$ is the bottom resistor in the voltage divider. Calculate $?R_E/10$. Is the condition satisfied? b. Calculate $V_B$ using the voltage divider equation. c. Calculate the $DC$ values of ${\mathrm{V}}_E,{\mathrm{I}}_{\mathrm{E}},{\mathrm{I}}_{\mathrm{C}}$, and ${\mathrm{V}}_{\mathrm{C}}$. Answer check: ${\mathrm{V}}_{\mathrm{C}}?8.1\mathrm{V}$ d. Calculate ${\mathrm{R}}_{\mathrm{in}}$, the resistance looking into the amplifier from ${\mathrm{V}}_{\mathrm{in}}$. Answer check: $1890?$ e. Calculate the voltage gain of the amplifier with no load. Answer check: -9.4 f. Calculate the voltage gain of the amplifier with a load resistor $R_L=1\mathrm{k}?$ placed at $V_{\text{out }}$. Answer check: -2.9