(Solved): The allowable shear stress for the material is allow=6ksi. Pin A is subjected to double she ...

The allowable shear stress for the material is $${?}_{\text{allow }}=6\mathrm{ksi}$$. Pin $$A$$ is subjected to double shear, whereas pin $$B$$ is subjected to single shear. (Figure 1) Determine the required diameter of the pins at $$A$$ to the nearest $$1/16\mathrm{in}$$. Express your answer as an exact decimal value and include appropriate units. Part B Figure 1 of 1 Determine the required diameter of the pin at $$B$$ to the nearest $$1/16\mathrm{in}$$. Express your answer as an exact decimal value and include appropriate units.