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The cross-section of a channel beam with double flanges and constant thickness throughout the section is shown in Figure Q2. You are required to derive the following expression for the distance "e" from the centerline of the web of the shear center "S". $e = \frac{3 b ^{2} ( h ^{2} _{1} + h ^{2} _{2} )}{h ^{3} _{2} + 6 b ( h ^{2} _{1} + h ^{2} _{2} )}$ Figure Q2: Channel Beam with double flanges.

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The cross-section of a channel beam with double flanges and constant thickness throughout the section is shown in Figure Q2. You are required to derive the following expression for the distance "e" from the centerline of the web of the shear center "S".

e = \frac{3 b ^{2} ( h ^{2} _{1} + h ^{2} _{2} )}{h ^{3} _{2} + 6 b ( h ^{2} _{1} + h ^{2} _{2} )}

Figure Q2: Channel Beam with double flanges.

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