(Solved): steel load calculation Figure 1 shows a plan view of a storage building. The floor slab is made of a ...

Figure 1 shows a plan view of a storage building. The floor slab is made of a steel deck that weights $$0.2\mathrm{KN}/{\mathrm{m}}^2$$, in addition to a flooring material of $$0.8\mathrm{KN}/{\mathrm{m}}^2$$. The slab resists a live load of $$1.2\mathrm{KN}/{\mathrm{m}}^2$$. The slab is supported by 9 purlins (P1, W200x42) and 2 Girders (G1, W250x73). The connections between columns and beams are shear connections. It is required to: a) Evaluate the ultimate (factored) applied loads (concentrated and uniformly distributed) on beam G1 (10\%) (Assume the load on $$P{1}^{?}=\frac{1}{2}$$ that on $$\mathrm{PI}$$ ) (Use clear drawing to show the final applied loads) b) Assuming that beam $$\mathrm{G}1$$ is subjected only to a uniformly distributed load of $$12\mathrm{kN}/\mathrm{m}$$, draw the bending moment and shear force diagrams for the beam G1 $$(10\%)$$ c) If the shear connection between $$\mathrm{Cl}$$ and $$\mathrm{G}1$$ was replaced with a moment connection, draw the bending moment diagram for the beam while being subjected to a uniformly distributed load of $$12\mathrm{kN}/\mathrm{m}(10\%)$$ a) $$\text{ wut }\begin{array}{rl}& =1.25(1)+1.5(1.2)\\ & =3.05\mathrm{kbca}\end{array}$$ load on Pl $$WPI=$$ load from slabt own weight $$?3.05\times 2+0.409\times 1.25=6.6$$ $$W{P}_1^1=\frac{1}{2}?{\mathrm{Wp}}^r=3.31\mathrm{kn}[\mathrm{m}$$ $$\begin{array}{l}{R}_{PI}=\frac{Wp1\times L_{pI}}{2}=\frac{6.61\times 6}{2}=\frac{19.83}{2}=9.965\mathrm{kn}\\ RP{)}^{?}=\frac{19.8}{}\end{array}$$ $$PC1=\frac{1}{3}(19.83\times 7+2\times 9.9/5+0.71\times 16)=56.69$$