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(Solved): Solve part b for the physics problem by using the formula below. 50% Part (a) Calculate the box' ...



Solve part b for the physics problem by using the formula below.\( 50 \% \) Part (a) Calculate the boxs volume, in cubic centimeters, ignoring the uncertainty in the volume. \( V=11.40 \qu\( \frac{\delta_{z}}{z}=\sqrt{\left(\frac{\delta x_{1}}{x_{1}}\right)^{2}+\left(\frac{\delta x_{2}}{x_{2}}\right)^{2}+\cdots+

Part (a) Calculate the box's volume, in cubic centimeters, ignoring the uncertainty in the volume. Correct! Part (b) Calculate the uncertainty, in cubic centimeters, in the volume you calculated in part (a).


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as given :x1±?x1=(1.9
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