(Solved): Solubility product of an iodate salt 1. In the experiment, you will react potassium iodate with cal ...

Solubility product of an iodate salt 1. In the experiment, you will react potassium iodate with calcium nitrate to produce a precipitate, Indicate the name of the precipitate formed: \[ \mathrm{KTO}_{3}+\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2} \longrightarrow \] 2. In this experiment the iodate \( \left(\mathrm{IO}_{3}{ }^{-}\right) \)and iodide ions \( \left(\mathrm{I}^{-}\right) \)react to produce molecular iodine \( \left(\mathrm{I}_{2}\right) \). Hence, in this redox reaction, a reactant is converted into products by simultaneous oxidation and reduction reactions. This type of redox reaction is referred to as disproportionation. Balance the corresponding disproportionation reaction. \[ 10_{3}{ }^{-}+1^{-} \longrightarrow \mathrm{I}_{2} \] 3. In this experiment thiosulfate \( \left(\mathrm{S}_{2} \mathrm{O}_{3}^{-2}\right) \) is used in a redox titration. This compound reacts with molecular iodide (I'). which has a reddish-brown color, to produce the ion colorless iodide \( \left(\mathrm{I}_{2}\right) \) and tetrathionate. Hence, when all thiosulfate is finished along with the titration the reaction becomes colored. Balance the corresponding redox reaction. \[ \mathrm{S}_{2} \mathrm{O}_{3}{ }^{-2}+\mathrm{I}_{2} \longrightarrow \mathrm{I}^{-}+\mathrm{S}_{4} \mathrm{O}_{6}{ }^{-2} \]