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(Solved): Sodium hydrooide reacts with carbon dioxide as follows: \( 2 \mathrm{NaOH}(s)+\mathrm{CO}_{2}(g) \r ...




Sodium hydrooide reacts with carbon dioxide as follows: \( 2 \mathrm{NaOH}(s)+\mathrm{CO}_{2}(g) \rightarrow \mathrm{Na}_{2}
Sodium hydroxide reacts with carbon dioxide as follows:
\( 2 \mathrm{NaOH}(s)+\mathrm{CO}_{2}(g) \rightarrow \mathrm{Na}_{2}
Sodium hydrooide reacts with carbon dioxide as follows: \( 2 \mathrm{NaOH}(s)+\mathrm{CO}_{2}(g) \rightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l) \) Which reagent is the limeng roactant whien \( 1.90 \mathrm{~mol} \mathrm{NaOH} \) and \( 1.00 \mathrm{~mol} \mathrm{CO}_{2} \) an atcued armant Part B How many moles of \( \mathrm{Na}_{2} \mathrm{CO}_{a} \) can bo produced? Express your answer using two decimal places. Sodium hydroxide reacts with carbon dioxide as follows: \( 2 \mathrm{NaOH}(s)+\mathrm{CO}_{2}(g) \rightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l) \) Part C How many moles of the excess reactant remain after the compleben of the reacicn? Expres5 your answer using two decimal places


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