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(Solved): \[ \sin (x y)=\cos (x+y) \] , then \( y^{\prime}=( \) \[ \text { C }-\frac{y \cos (x y)+\sin (x+y)} ...
\[ \sin (x y)=\cos (x+y) \] , then \( y^{\prime}=( \) \[ \text { C }-\frac{y \cos (x y)+\sin (x+y)}{x \cos (x y)+\sin (x+y)} \] Single Choice (total7question, 28.0score) 6. (4.0score) \[ \int x e^{-x^{2}} d x=() \] \[ \text { C }-\frac{1}{2} e^{-x^{2}}+C \text {. } \] Single Choice (total7question, 28.0score) 7. (4.0score) \( \int \cos 2 x d x=(\quad) \) D \( \frac{1}{2} \sin 2 x+C \). Fill in the Blank (total9question, 36.0score) 8. (4.0score) \[ \lim _{x \rightarrow 1} \frac{x^{2}-1}{x-1} \]
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Solution- Given that sin?(xy)=cos?(x+y) we find y?=? Differentating with respect to x on both the sides we have cos?(xy)[y+xy?]=?sin?(x+y)[1+y?] ?ycos
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