(Solved): Simplified Presentation of Motor Feeder Circuit a) Uncompensated motor (with ...

???????

Simplified Presentation of Motor Feeder Circuit a) Uncompensated motor (with the jumper removed) b) Fully compensated motor (with the jumper inserted and the value of \( X c=-j 1200 \Omega \) ) c) Over-compensated motor (with the jumper inserted and the value of \( X c=-j 600 \Omega \) ) Record the results in table \( 4.2 \). Hint: You may need to use the wattmeter values to determine power factor, \( p f=P / S \). Table 4.2- Simulation Results