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Shown below is the structure of natamycin. It contains two functional groups that could be potenti ...
Shown below is the structure of natamycin. It contains two functional groups that could be potentially ionized. The \( \mathrm{pK}_{e} \) values for natamycin are \( 4.6 \) and 8.4. a. Match the \( \mathrm{pK}_{\mathrm{a}} \) values provided to the appropriate functional groups and identify if the functional group is acidic or basic. b. Using the Henderson-Hasselbalch equation, calculate the percent ionization that occurs for each of these functional groups at an intestinal \( \mathrm{pH}=6.2 \). The most basic functional group present within the structure of ranitidine has a \( \mathrm{pK}_{\mathrm{s}}=8.2 \). Identify this functional group and calculate the \( \mathrm{pH} \) that is necessary for this functional group to be \( 70 \% \) ionized.
3 Q: a. Ans:: Carboxylic acid PKa=4.6 (Acidic) Primary amine PKa=8.4 (Basic) b. Ans:: Percent in Ionized Form= 99.4% at PH=6.2 4 Q: Ans:: PH = 8.6 Explanation: 3 Question: b . Ans:: For the carboxylic acid, the pKa = 4.6 and the pH = 6.2. Using the H