(Solved): Set up a triple integral for the volume of the solid. Do not evaluate the integral. The solid bound ...

Set up a triple integral for the volume of the solid. Do not evaluate the integral. The solid bounded by \( z=\sqrt{9-x^{2}-y^{2}} \) and \( z=0 \) \[ \int_{-3} \int_{-\sqrt{9-x^{2}}} \int_{0} d z d y d x \] [-/1 Points] LARCALC11 14.6.503.XP. Use a triple integral to find the volume of the solid shown in the figure. \[ z=36-x^{2}-y^{2} \] Use a triple integral to find the volume of the solid bounded by the graphs of the equations. \[ z=3 x^{2}, y=2-2 x, \text { first octant } \] \( \int_{0} \int_{0} d z d y d x= \)