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(Solved): Question 4 (i) Solve for 0\deg <\theta <360\deg 6sin^(2)\theta -sin\theta -2=0 (ii) Prove tha ...
Question 4
(i) Solve for 0\deg <\theta <360\deg
6sin^(2)\theta -sin\theta -2=0
(ii) Prove that
cscA-(sinA)/(cosA)=cotA
(iii) Express as partial fractions
(5x^(2)+28x+47)/((x-1)(x+3)(x+4))
(iv) Given sin\theta =(1)/(2), find cos\theta and tan\theta for \theta in[0\deg ,90\deg ]