(Solved): Q13. A parabolic vertical curve connects a +4.5% grade with a 4% grade on a rural highwa ...

Q13. A parabolic vertical curve connects a $+4.5\%$ grade with a $?4\%$ grade on a rural highway at station $875+25.4$ and tangent elevation of $512.6\mathrm{ft}$. The length of the curve is $550\mathrm{f}$. ${\mathbf{X}}_{\text{ligh or low }}=(\mathbf{L})\left({\mathbf{G}}_1\right)/\left({\mathrm{G}}_1?{\mathbf{G}}_2\right)$ $\begin{array}{l}E=(A)(L)/800\\ y=(4)(E)(X/L{)}^2.\end{array}$ The location of the PVC is at: (a) $870+50.4$ (b) $874+50.4$ (c) $872+504$ (d) $875+25,4$ Q14. The elevation of the $\mathrm{PVC}$ is at: (a) $510.225\mathrm{R}$ (b) $500.225\mathrm{n}$ (c) $512.600\stackrel{?}{\mathrm{A}}$ (d) $505.225\mathrm{ft}$ (e) $500.000\mathrm{n}$ $?8$ Q15. Thelocation of the high point is at: Station af PVt (a) $875+25.40$ (b) $875+50.40$ (c) $875+41.58$ (d) $874+41,58$ $=PVI+\frac{1}{2}$ $x=\left(875+2.4^2\right)+\frac{580}{2}$ Q16. The curve elevation of the high point is at: (a) $512.600\mathrm{n}$ (b) $501.600\mathrm{f}$ (c) $513.328\mathrm{f}$ (d) $506.776\mathrm{ft}$ Q17. The curve elevation of the middle point is at: (a) $512.600\mathrm{ft}$ (b) $506.776\mathrm{A}$ (c) $506.756\mathrm{ft}$ (d) $513.328\mathrm{ft}$