(Solved): Propanone and iodine react in acidic conditions according to the equation: CH3COCH3+I2I ...

Propanone and iodine react in acidic conditions according to the equation: ${\mathrm{CH}}_3{\mathrm{COCH}}_3+{\mathrm{I}}_2?I^2{\mathrm{CH}}_2{\mathrm{COCH}}_3+\mathrm{HI}$ A student studied the kinetics of this reaction using hydrochloric acid and a solution containing propanone and iodine. The following rate equation was deduced from the results: $\text{ rate }=k\left[{\mathrm{CH}}_3{\mathrm{COCH}}_3\right]\left[{\mathrm{H}}^{+}\right]$ What is the overall order for this reaction?