(Solved): Problem 40: A masonry dam has a trapezoidal section: one face is vertical, width at the top is 60 cm ...

Problem 40: A masonry dam has a trapezoidal section: one face is vertical, width at the top is 60 cm and at the bottom is 3 m. The dam is 7 m high with the vertical face subjected to water pressure. If the depth of water is 5 m, where will the resultant force intersect the base?

1. The masonry dam of Problem 40 has its inclined face subjected to pressure due to a depth of 5m of water. If there is no uplift pressure, where will the resultant intersect the base? Specific weight of concrete is 23.54 KN/m^3.

2. A concrete dam is triangular in cross section and 30 m high from the horizontal base. If water reaches a depth of 27 m on the vertical face, what is the minimum length of the base of the dam such that the resultant will intersect the base within the middle third? What minimum coefficient of friction is required to prevent sliding? Determine the pressure distribution along the base.

3. Shown in Fig. V is an overflow dam. If there is no uplift pressure, determine the location of the resultant.

4. The timber shown in Fig. EE is 30 cm square and 6 m long, having a specific gravity of 0.50. A man standing at a point 60 cm from one end causes that end to be just submerged. Find the weight of the man.

5. A submarine of 10,700 KN displacement has its center of gravity 30 cm from its center of volume. What is the righting couple when it is submerged in sea water and the angle of heel is 5°?

6. A log 30 cm in diameter weighs 4900 N/m^3. What is its shortest length so that it may float in water with the axis horizontal?

7. A rectangular scow 9.15 m wide by 15.25 m long has a draft of 2.44 m in fresh water. Its center of gravity is 4.60 m above the bottom. Determine the height of the scow if with one side just at the point of submergence, the scow is in unstable position.