(Solved): plz solve , maximum height case Two projectiles following the same parabolic trajectory, are fo ...

plz solve , maximum height case

Two projectiles following the same parabolic trajectory, are found to be in the same horizontal level, separated by a distance of $1\mathrm{m},2$ second after the second particle was projected. Both the particles were projected with the same initial velocity from the same point on level ground. In respect of their motion, which of the following statements will be true ? A) the horizontal range of the parabolic path is $(1+4\mathrm{V})$, where $\mathrm{V}$ is the (constant) horizontal component of velocity in the path B) the maximum height of the parabolic path $=\frac{1}{2}g{\left(2+\frac{1}{2V}\right)}^2$ C) the total time of flight in the parabolic path for each particle $=4\mathrm{s}$ D) the particles will reach the ground in an interval of time $=2\mathrm{s}$